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Turunan Pertama Fungsi Trigonometri f(x) = 2 sin 3x + 3 cos 2x , Maka Nilai f’(π/2) = 0

f(x) = 2 sin 3x + 3 cos 2x.

Nilai f’(π/2) adalah …

A. -2

B. -1

C. 0

D. 1

E. 2

 

PEMBAHASAN

f(x) = u + v, Maka f’(x) = u’ + v’

u = 2 sin 3x

u’ = 3 . 2 cos 3x

u’ = 6 cos 3x

 

v = 3 cos 2x

v’ = 2 . 3 (-sin 2x)

v’ = -6 sin 2x

 

f’(x) = 6 cos 3x -6 sin 2x

f’(π/2) = 6 cos 3π/2 – 6 sin 2π/2

f’(π/2) = 6 . 0 – 6 . 0

f’(π/2) = 0 (C)

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